Is this the correct internal air space measurement for my enclosure? - Ranger-Forums - The Ultimate Ford Ranger Resource


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Old 04-19-2006
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Is this the correct internal air space measurement for my enclosure?

I'm thinking of going ahead and keeping my old enclosure if the internal air space is right. I already asked this question on caraudioforum and I got a respounce from a member. I just want to make sure its right. I'll copy the link to the forum.

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Thanks.
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Old 04-19-2006
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Old 04-20-2006
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please, can anybody confirm this?
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Old 04-20-2006
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Where the hell'd he get those measurements from??? I gotta go to class and work then class again, so I'll try my hand at it tonight. Is the box made from 3/4" or 1/2" MDF????

It's sealed, too, right?
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Old 04-20-2006
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Quote:
Originally Posted by rolla_guy72
Where the hell'd he get those measurements from??? I gotta go to class and work then class again, so I'll try my hand at it tonight. Is the box made from 3/4" or 1/2" MDF????

It's sealed, too, right?
The mdf is .5 inches.

I measured the enclosure and it came out to those dimensions.

14.5 inches hight(top-bottom)
15.25 inches width (side-side)
depth or length 1(top) 7.75 inches
depth or length 2(bottom) 18 inches

then, I took the average of the depth or length 1 and 2 and it came out to
=Avereged 12.875 inches

This is a sealed enclosure.

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Old 04-21-2006
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well, someone else got a different measurement and it came out to being 1.314 cu. ft. . The original measurement was 1.22 cu.ft. . So, please, I need someone to confirm this.
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Old 04-21-2006
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Alright to get the volume of your box, you will have to find the area of the trapazoidal side panel, then multiply that by the width of the box. And also we'll have to subtract the (width of the MDF)*2 to get the interior measurements of the box. SO.........

The area of a trapezoid is found by averaging the two parallel sides then multiplying them by the height of the trapezoid. In your case---> 11.875*13.5 = 160.3125

Now, we multiply the area of the trapezoid by the width of the box---> 160.3125*14.25 = 2284.4531

And finally, we divide that number by the "magic" (one cubic foot in inches)number for box builders... 12*12*12 or 1728---> 2284.4531/1728 = 1.3220214

And there's your box's volume.... 1.322 ft3
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Old 04-21-2006
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thanks a bunch, now I'm going to ahead and keep it and put my jl w3 sub in it.
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