Looking for a complete F7 [7.5 4.10 Limited Slip/Posi Traction] rear end. If the brakes are missing thats fine just more excuse to do a disc conversion before I swap it.Willing to travel a little if the price is right but I don't wanna even imagine what shipping one would cost.

 

Check car-part.com

Look for "rear axle assembly"
Wrecking yards call them "locking" differentials when they are limited slip(L/S)

7.5" or 8.8" are interchangeable, just FYI, just bolt in no changes needed
8.8" is code R7 for L/S
And there were more 8.8" with L/S, as most 4x4 Rangers had L/S rear axles

 

Yeah but I don't think a 2.3 would like a 8.8 very much.

 

????

It wouldn't care at all, just FYI
7.5" was used because its cheaper, no other reason
Same size axles and tubes as 8.8"
Just the cost new is less so Ford can build it a little cheaper

But for your purpose, looking for a 4.10 L/S rear differential, either will do, no drawback using a 7.5" or 8.8"

 

Really? I thought 8.8 required more power and would make a smaller engine struggle?

 

Nope, it can handle more power/torque, but doesn't require it

 

Do you have any references? That just doesn't sit right with me? Its bigger and therefore takes more power to move.

 

I think you are referencing the weight only of the differential and housing, and yes, there would be a few more pounds added to the total weight
But as far as the torque/power needed to spin a 7.5" and 8.8", with the same ratio, there shouldn't any noticeable difference
I don't think there has even been a study on that

The leverage for the pinion to move the 7.5" ring gear and the 8.8" ring gear should be the same, maybe a little less for the 8.8" because its farther away from the center(axles) so has better leverage to move them, so that may compensate for the weight difference

 

No I'm not concerned at all with weight it just makes sense to me that its a larger gear and needs more torque from the engine to get it turning.